Re: [MATHEDCC] Standard form, et. al
Wayne Mackey (wmackey@comp.uark.edu)
Wed, 4 Jun 1997 10:42:03 -0600
>The 0 is Imaginary since 0i=i0=0 from its own property as the absorbant
>element for the multiplication in any subset of the complex set. And as
>the neutral element of the addition 0i + bi = (0+b)i = bi closure
> bi + 0i = (b+0)i = bi and if b=0 then bi=0i=0
>Thus 0 responds to the definition of element of the complex set and ,
>therefore it can be considered as a pure Imaginary number.
>
>
I think I was wrong in my previous message. Since the pure imaginary
numbers are on the (usually) vertical axis and since 0 (= 0 + 0i) is on
that axis, I guess you could call it a pure imaginary. Golly, thats the
first time I was ever wrong. And of course the previous sentence is the
second time.
wayne
Wayne F. Mackey
University of Arkansas
P.O. Box 2441
Fayetteville, AR 72702
wmackey@comp.uark.edu
http://comp.uark.edu/~wmackey
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