Re: [MATHEDCC] Standard form, et. al
Bev Broomell (brb@cheerful.com)
Wed, 04 Jun 1997 23:01:57 -0400
Wayne Mackey wrote:
>
> >The 0 is Imaginary since 0i=i0=0 from its own property as the absorbant
> >element for the multiplication in any subset of the complex set. And as
> >the neutral element of the addition 0i + bi = (0+b)i = bi closure
> > bi + 0i = (b+0)i = bi and if b=0 then bi=0i=0
> >Thus 0 responds to the definition of element of the complex set and ,
> >therefore it can be considered as a pure Imaginary number.
> >
> >
> I think I was wrong in my previous message. Since the pure imaginary
> numbers are on the (usually) vertical axis and since 0 (= 0 + 0i) is on
> that axis, I guess you could call it a pure imaginary. Golly, thats the
> first time I was ever wrong. And of course the previous sentence is the
> second time.
Cute, Wayne!
Bev
(See other messages for my signature line)
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