Re: [MATHEDCC] Indeterminate Form

yoshiwbw@SMTPLINK.LACCD.EDU
Tue, 11 Mar 97 19:42:59 pdt

Actually, any logician will cheerfully inform you that 0^0
is indeed defined to be 1. However, the analysts are
unhappy with this definition, probably because the function
x^y will remain discontinuous at the origin, even restricted
to limits approaching from the first quadrant.

Bruce Yoshiwara

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The TI92 and perhaps other calculators have 0^0 as a determinate form.
Can someone explain why this is so? I have always thought that it was
an indeterminate form. Are "they " wrong or am I thinking
incorrectly? Thanks for your help.

Andrew Bulleri
Howard Community College
Little Patuxent Parkway
Columbia, Md 21044

Phone 410-964-4926 (O)
Fax 410-715-2401
EMail ABULLERI@CCM.HOWARDCC.EDU

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