>
> (0,3) =3D (0,-3) =3D -(3,0)
>
Ah, I see I flubbed it. Silly me.
(0,3) =3D (-3,0) =3D -(3,0)
would have been correct.
Apologies.=20
Kirby
PS: Note that in the full-blown quadrays system,
we do have the option to normalize such that the
sum of the coordinates always adds to zero. This
brings quadrays closer to what's already in the=20
literature under the heading of "simplicial=20
coordinates" (not the same as barycentrics).
However, the 4-tuples are usually read as talking
about some 4-dimensional (trans 3-d) shape, whereas
the interpretation given at my website is strictly
about ordinary volume (so-called Euclidean space).
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